Options and Futures
\[C\] \[\large +\] \[ -P\]
\[ C - P\]
\[S_0\] \[\large +\] \[ -K e^{-rT}\]
\[ C - P\]
\[\Large C - P = S_0 - K e^{-rT}\]
Definition: Long a call and short a put at the same strike price and same expiration date is equivalent to borrowing to buy the underlying asset.
Conditions:
Various versions:
What happens if the parity does not hold? Buy low, sell high.
Synthetic shorting: long put + short call
Do you need margin for it?
Does it matter for the stock price?
Two observations from the diagram: 1. The payoff of the call option is positive \(\implies\) \[C > 0\] 2. The payoff of the call option (solid) is better than borrow to buy the stock (dashed) \(\implies\)
\[C > S_0 - K e^{-rT}\]
From the put-call parity, knowing the put price \(P\) is positive, we have
\[C = S_0 - K e^{-rT} + P > S_0 - K e^{-rT}\]
Taken together, we have the lower bound of the call option: \[C > \max(0, S_0 - K e^{-rT})\]
\[C < S_0 - K e^{-rT} \implies \underset{\text{Buy low}}{\underbrace{C - P}} < \underset{\text{Sell high}}{\underbrace{S_0 - K e^{-rT}}}\]
How do we implement this?
Now:
Net gains: \(S_0 - K e^{-rT} - (C - P) > 0\)
At maturity:
Under regular conditions, the call price converges to the lower bound when it’s deep.
Deep out of the money: \[K \gg S_0 \to 0 \implies C \to 0\]
Deep in the money: \[K \ll S_0 \to \infty \implies C \to S_0 - K e^{-rT}\]
The payoff of a call option is less than the payoff of the stock itself.
\[C < S_0\]
What happens if the upper bound is violated?
Sell a call and use the cash to buy the stock
\[P > K e^{-rT} - S_0\]
From the put-call parity, knowing the call price \(C\) is positive, we have
\[P = K e^{-rT} - S_0 + C > K e^{-rT} - S_0\]
Taking together, we have the bounds on the put option: \[ \max(0, K e^{-rT} - S_0) < P < K e^{-rT}\]
Under regular conditions, the put price converges to the lower bound when it’s deep.
Deep out of the money: \[K \ll S_0 \to \infty \implies P \to 0\]
Deep in the money: \[K \gg S_0 \to 0 \implies P \to K - S_0 e^{-rT}\]